Answer:
u = - 38.85 m/s^-1
Explanation:
given data:
acceleration = 2.10*10^4 m/s^2
time = 1.85*10^{-3} s
final velocity = 0 m/s
from equation of motion we have following relation
v = u +at
0 = u + 2.10*10^4 *1.85*10^{-3}
0 = u + (21 *1.85)
0 = u + 38.85
u = - 38.85 m/s^-1
negative sign indicate that the ball bounce in opposite directon
The Virtual Laboratory is an interactive environment for creating and conducting simulated experiments: a playground for experimentation. It consists of domain-dependent simulation programs, experimental units called objects that encompass data files, tools that operate on these objects
Answer:
B. 7.07 m/s
Explanation:
The velocity of the stone when it leaves the circular path is its tangential velocity, 
, which is given by
where 
is the angular speed and 
is the radius of the circular path.
is given by
where 
is the frequency of revolution.
Thus
Using values from the question,
<em>Note the conversion of 75 cm to 0.75 m</em>
Answer:Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.
Explanation:
Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.
