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Maurinko [17]
2 years ago
14

What is the area of the trapezium?

Mathematics
2 answers:
cluponka [151]2 years ago
6 0

Answer:

156 cm²

Explanation:

This figure is a trapezium.

Formula of Area of Trapezium = 1/2 × (a + b)  × height

Here given:

  • a = 9 cm
  • b = 30 cm
  • h = 8 cm

==============

Area of trapezium: 1/2  × (9 + 30)  × 8 = 156 cm²

love history [14]2 years ago
5 0

Answer:

area of the trapezium is 156

Step-by-step explanation:

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The length of a rectangle is five times it’s width if the area of the rectangle is 320m^2 find its perimeter
BlackZzzverrR [31]

Answer:

Perimeter of the rectangle = 96 meters.

Step-by-step explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area  = 320 sq meters

Now, Area of a Rectangle  = Length x Width

⇒  320  = K x  5K

or,5K^{2} = 320\\or, K^{2}  = \frac{320}{5}   = 64

So, the vlue of K = 8 or, K = -8

But as K represents a length hence, K ≠ -8

So, the <u>width of the rectangle = 8 meters</u>

and the<u> length  of the rectangle = 8 x 5 = 40 meters</u>

Now, Perimeter = 2(length + width)

                            = 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.

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Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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