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oksian1 [2.3K]
2 years ago
11

Fifteen times the square of a non-zero number is equal to 12 times the number. What is the number?

Mathematics
1 answer:
salantis [7]2 years ago
4 0
The answer is 0.8

15x^2=12x

15x=12

x=12/15  = 4/5   so the answer is 0.8
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Sofia bought $38 worth of video games. She had a coupon that allowed her to save 8% on her purchases.
Alik [6]

Answer:34.96 (answer to what is her purchase price before tax)

Step-by-step explanation:38*(1-.08)

6 0
2 years ago
Find the diameter of the circle. Assume the leg of the triangle is tangent to the circle. Round any decimals to the nearest tent
Anvisha [2.4K]

Answer:

8.7 units

Step-by-step explanation:

Given is a right angled triangle (because the segment with 5 units length is tangent to circle. Tangent is perpendicular to RADIUS or diameter)

Let the length of the diameter be d units

By Pythagoras Theorem:

d =   \sqrt{ {10}^{2} -  {5}^{2}  }  \\  =  \sqrt{100 - 25}  \\  =  \sqrt{75} \\  =  8.66025404 \\  = 8.7 \: units

3 0
2 years ago
Can someone please help me I’m struggling
blagie [28]

Answer:

point form is (2,-1), equation form is x= 2, y=-1

Step-by-step explanation:

3 0
3 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
3 years ago
A number cube is rolled several times. The results are shown in the table below. What is the ratio of rolling a 2 to rolling a 5
oksano4ka [1.4K]
1/6 chance of rolling any side
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3 years ago
Read 2 more answers
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