Answer:
<h2>
-29.61m/s</h2>
Step-by-step explanation:
Given the distance of fall of the student in term of the time t expressed by the equation s(t) = −16t² + 8√t, to get the average speed of fall of the pencil after 2.8 secs, we will need to differentiate the given function first since Velocity is the change in distance of a body with respect to time i.e
V = d(s(t))/dt
s(t) = −16t² + 8t^1/2
V = -32t+1/2(8)t^(1/2 - 1)
V = -32t+4t^-1/2
The average speed of the fall Using the fact that the pencil hit the ground in exactly 2.8 seconds, will be gotten by substituting t = 2.8 into the resulting equation.
V = -32t+4(2.8)^-1/2
V = -32t+4/√2.8
V = -32+4/1.6733
V = -32+2.391
v = -29.61m/s
<em>Hence the average speed of the fall is -29.61m/s</em>
Answer: Graph D
Step-by-step explanation: Got it right on plato
10x^2y^-2 = 10 x (-1)^2 x (-2)^-2 = 10 x 1 x 1/4 = 10/4 = 2 1/2
Answer:
b bc its the right one :D i think
