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Ludmilka [50]
3 years ago
6

Given that X = {April, August}, then ξ = {months that begin with the letter A}. True or False?

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

False

Step-by-step explanation:

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What is the value of sinθ given that (5, −12) is a point on the terminal side of θ ?
LekaFEV [45]
X = 5 and y = -12  is in the fourth quadrant. Hypotenuse =  13

sin theta  =   opposite / hypotenuse = -12 /13
5 0
3 years ago
Read 2 more answers
If = 12 –3 a,find the value ofxwhen a= 8
faust18 [17]

Answer:

-12

Step-by-step explanation:

x = 12-3a

When a=8:

x = 12-3(8)

x = 12 - 24

x = -12

5 0
2 years ago
Any help with this plzzz?????
Harrizon [31]
1.
a.11/12=less than one

b. 77/72= greater than one

c.23/60= less than one

d. 31/56= less than one

2. <
8 0
3 years ago
Use the following information to answer problems 14-16: Suppose that in a large metropolitan area, 82% of all households have ca
Helen [10]

Answer:

66.6% or 0.66

Step-by-step explanation:

82% or 0.82 of All households have cable TV.

X = The number of households in a group of 6, that have cable TV.

You wish to find the proportion or percentage of groups for which EXACTLY 4 of 6 households will have cable TV.

82% of 6 is = 4.92

Approximately 4.92 out of 6 households, have cable TV.

Using this figure, you can now find out what % of 6 will give you 4.

Cross multiply:

0.82 - 4.92

M - 4

M = (4×0.82) ÷ 4.92 = 3.28÷4.92 = 0.666

Hence, 66.6% of 6 households, have cable TV. In other words, exactly 4 households (X=4) have cable TV.

To test, you can find what 66% of 6 is. You will get 4.

6 0
3 years ago
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
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