Select whether each equation has no solution, one solution, or infinitely many solutions

1 answer:

6 0

Once put into the quadratic formula the numbers in the square root of they are negative no solutions if it is 0 then 1 solution if more then more than one solution

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Sindrei [870]

Answer:

[See Below]

Step-by-step explanation:

Look at the "Fraction" column, all the fractions in this column must add up to 1 (because the whole bag contains only Red, Green, Blue or Other coloured beads).

So we work out the sum of missing fractions: $\frac{1}{12} + \frac{1}{4} = \frac{1}{12} + \frac{3}{12} = \frac{4}{12} = \frac{1}{3}$

And so we know the fractions in the missing boxes must add up to $1 - \frac{1}{3} = \frac{2}{3}$ .

This means that the number of blue and green beads is 2/3rds of the total number of beads in the bag. There are 12+4=16 blue+green beads so

$\frac{2}{3} \times \text{Number of beads} = 16 \Rightarrow \text{Number of beads} = 24$ .

So if there are 24 beads in the bag, then the red beads are 1/12th of 24 which is 2 and the other beads are 1/4 of 24 which is 6.

Finally to complete the missing fractions: there are 12 blue beads and 24 in total so the fraction of blue beads is 12/24 = 1/2. Similarly, there are 4 green beads so the fraction of green beads is 4/24 = 1/6.

(I thought this was a very tricky question. Let me know in the comments if something doesn't make sense, or if you need more explanation on any part, or even if you spot an easier way to do it that I can't.)

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I think im pritty sure its A

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