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MA_775_DIABLO [31]
3 years ago
14

Select whether each equation has no solution, one solution, or infinitely many solutions

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Once put into the quadratic formula the numbers in the square root of they are negative no solutions if it is 0 then 1 solution if more then more than one solution

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Give an example of this when adding two rationalnumbers with different signs and provide the product.
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\begin{gathered} \frac{4}{5}+-\frac{8}{3}=-\frac{28}{15} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{32}{15} \end{gathered}

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\begin{gathered} \frac{4}{5}\text{ and - }\frac{8}{3} \\ \text{adding} \\ \frac{4}{5}+-\frac{8}{3}=\frac{4}{5}-\frac{8}{3} \\ \frac{4}{5}-\frac{8}{3}=\frac{4\cdot3-5\cdot8}{5\cdot3}=\frac{12-40}{15}=-\frac{28}{15} \\ \text{ product} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{4\cdot8}{5\cdot3}=-\frac{32}{15} \end{gathered}

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