Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
5x+34=-2(1-7x)
Steps:
5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9
Answer: x= 4
So, the equation is y=mx + b and you want to solve for b to find the y intercept.
-5=2(4) + b
-5=8+b
subtract the 8
-13=b
the equation is y = 2x - 13
Answer:
A15+B10=cents
Step-by-step explanation: