Answer:
The answer is below
Step-by-step explanation:
Let Q represent the amount of salt in the tank at time t.


Y=a(x-h)^2+k
-5=a(1-0)^2+2
-5=a+2
-3=a
y=-3x^2+2
Answer:
4x-15
Step-by-step explanation
You just multiply -5 and -3 to simplify this.
Answer:
A parallelogram is a two-dimensional geometrical shape whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length. The Sum of adjacent angles of a parallelogram is equal to 180 degrees.
Step-by-step explanation:
Answer:
28cm
Step-by-step explanation:
A=a+b
2h=4+10
2·4= 28cm