Answer:
x = 2000 cameras
Step-by-step explanation:
C(x) Total cost in producing x units
C- = C(x) /x Average cost of producing x units x > 0
Cannon Precision Instrument
C (x) Total monthly cost for producing x units of M1 cameras
is C(x) = 0.0025x² + 80x + 10000
Then average cost of producing x cameras M1 is
C-(x) = ( 0.0025x² + 80x + 10000) /x
C-(x) = 0.0025x + 80 + 10000/x
Taking derivatives on both sides of the equation
C-´(x) = 0.0025 - 10000/x²
Then
C-´(x) = 0
( 0.0025x² - 10000 ) / x² = 0
0.0025x² - 10000 = 0
x² = 10000 /0.0025 x² = 4000000
x = 2000 cameras
2×$15.99=31.98
+ 4×$11.99=47.96
---------------
$79.94
:. $79.94 is the cost.
21. >
22. Distributive Property
Answer:
the answer is approximately 48.05.
Step-by-step explanation: You can either use a calculator or estimate knowing that 50 is the square root of 2500, which is slightly above 2309. You can also use differentials and calculus to find an approximation.
