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svetoff [14.1K]
3 years ago
9

Please help ASAP

Chemistry
2 answers:
aev [14]3 years ago
5 0

Answer:

1st one is correct, Igneous rocks are formed when molten rock cools and hardens.

Annette [7]3 years ago
3 0

Answer:

igneous rocks have distinct layers that represents the time period

Explanation:

They are not formed overtime, nor have layers. They are just hardened lava.

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A melting point of a substance is a point at which the sample or substance start converting in liquid. For most substances, melting and freezing points are approximately equal. For example, the melting point and freezing point of mercury is 234.32 kelvins (−38.83 °C or −37.89 °F). Hope this helped!! :)

5 0
3 years ago
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The Haber reaction for the manufacture of ammonia is: N2 + 3H2 → 2NH3 Without doing any experiments, which of the following can
Dimas [21]

Answer :  The correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

The expression for rate of reaction :

\text{Rate of disappearance of }N_2=-\frac{d[N_2]}{dt}

\text{Rate of disappearance of }H_2=-\frac{1}{3}\frac{d[H_2]}{dt}

\text{Rate of formation of }NH_3=+\frac{1}{2}\frac{d[NH_3]}{dt}

From this we conclude that,

\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Hence, the correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

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