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Vikki [24]
3 years ago
9

The Earth and the spaceship both have mass. The astronaut is attracted to Earth by gravity, but he is not attracted to the space

ship. Explain.
Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0
The spaceship does not have any gravitational pull. A spaceship can not produce its own gravity like Earth does.
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Ethanol has a density of 0.791 g/mL. A student pipets enough volume in mL to obtain 120.0 g.
Elza [17]

Answer:

I can't answer that Po sorry

5 0
2 years ago
Which of the following is an asteroid? A: A shooting star B: A big chunk of space rock C: A small comet D: A small meteor
lora16 [44]

Answer:

B: A big chunk of space rock

Explanation:

asteroids are basically known as minor planets.

whereas shooting star is some dust burning while entering earths atmosphere.

on the other hand comet is some icy material consisting of gases.

and meteor is a very very small rocky or metallic body.

7 0
4 years ago
Which selection contains elements that are NOT all in the same group?
Volgvan

Answer:

Iron, copper , calcium

Explanation:

Iron , copper and calcium are present in three different groups.

Iron is present in group eight.

Copper is present in group eleven.

Calcium is present in group two.

Sodium , potassium and rubidium are present in same group i.e. group one. These are alkali metals.

Fluorine, chlorine and bromine are present in group seventeen. These are halogens.

Argon, Krypton and xenon are present in same group i.e, group eighteen. All are these noble gases.

4 0
3 years ago
A conclusion in science states whether or not a hypothesis is correct<br> or not?
Fantom [35]

Answer:it do not states

Explanation:

3 0
4 years ago
What volume of a 0.00945-M solution of potassium hydroxicce would be required to titrae 50.00mL of a sample of acid rain with a
Zepler [3.9K]

<u>Answer:</u> The volume of HBr solution required is 130.16 mL

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=2\\M_1=123\times 10^{-4}M=0.0123M\\V_1=50mL\\n_2=1\\M_2=0.00945M\\V_2=?mL

Putting values in above equation, we get:

2\times 0.0123\times 50=1\times 0.00945\times V_2\\\\V_2=130.16mL

Hence, the volume of KOH solution required is 130.16 mL

5 0
4 years ago
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