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KIM [24]
3 years ago
10

What is the new concentration of a solution after 250mL of 2.5M sulfuric acid is diluted to a final volume of 700mL?

Chemistry
1 answer:
o-na [289]3 years ago
6 0

Answer:

The new concentration of the solution is 0.89 M.

Explanation:

In chemistry, dilution is the reduction in concentration of a chemical in a solution. This is accomplished by adding more solvent to the same amount of solute.

So, in a dilution, the amount of solute does not vary, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

In this case:

  • Ci= 2.5 M
  • Vi= 250 mL
  • Cf=?
  • Vf= 700 mL

Replacing:

2.5 M* 250 mL= Cf* 700 mL

Solving:

Cf=\frac{2.5 M*250 mL}{700 mL}

Cf= 0.89 M

<u><em>The new concentration of the solution is 0.89 M.</em></u>

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