Question

What is the new concentration of a solution after 250mL of 2.5M sulfuric acid is diluted to a final volume of 700mL?

Answer 1

Answer:

The new concentration of the solution is 0.89 M.

Explanation:

In chemistry, dilution is the reduction in concentration of a chemical in a solution. This is accomplished by adding more solvent to the same amount of solute.

So, in a dilution, the amount of solute does not vary, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

• Ci: initial concentration
• Vi: initial volume
• Cf: final concentration
• Vf: final volume

In this case:

• Ci= 2.5 M
• Vi= 250 mL
• Cf=?
• Vf= 700 mL

Replacing:

2.5 M* 250 mL= Cf* 700 mL

Solving:

$Cf=\frac{2.5 M*250 mL}{700 mL}$

Cf= 0.89 M

The new concentration of the solution is 0.89 M.