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2 years ago

6

what is true about the solutions of a quadratic equation when the radical in the quadrant formula is negative

1 answer:

lisov135 [29]2 years ago

3 0

Since the square root of a negative number is not a real number, then a negative radical will result in no real solution.

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If we were to do this equation how would I solve it

s344n2d4d5 [400]

Answer:

$- 6 \frac{1}{3}$

Step-by-step explanation:

$\frac{10}{3} - \frac{1}{3} - \frac{29}{3} - ( - \frac{1}{3} ) \\ \\ = \frac{10}{3} - \frac{1}{3} - \frac{29}{3} + \frac{1}{3} \\ \\ = \frac{10}{3} - \frac{29}{3} - \frac{1}{3} + \frac{1}{3} \\ \\ = \frac{10 - 29}{3} \\ \\ = \frac{ - 19}{3} \\ \\ = - 6 \frac{1}{3}$

6 0

3 years ago

Lettets a, b, c, and d are angle measures Which should equal 105 to prove false g

GrogVix [38]

Answer:

a equals 105°

Step-by-step explanation:

angles in a straight line add up to 180°

a+75=180

a=180-75

a=105°

4 0

2 years ago

382215 HELP ME WITH THIS QUESTION!

Rom4ik [11]

Answer:

T'= (-4,-3)

U'= (5,-3)

V'= (-5,2)

Please mark me brainlest

5 0

2 years ago

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

2 years ago

Megan charges %5.00 for each hour, (h), she babysits. Last week, the total amount she earned by babysitting was $65.00.

mel-nik [20]

Answer:

B

Step-by-step explanation:

To find how many hours she worked you must divide $65 by $5 and B is the only equation where you can do that.

8 0

2 years ago