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3 years ago

7

What 4 number add up to 47

1 answer:

vagabundo [1.1K]3 years ago

4 0

20 + 6 + 11 + 10 adds up to 47

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Rachel has bought 24 pounds of dog food. She feeds her dog 3/4 pounds for each meal. For how many meals will the food last?

lilavasa [31]

Answer:

32 meals

Step-by-step explanation:

24/.75 = 32

- Please let me know if you need a further explanation

7 0

3 years ago

Ashton bought 5 cans of olive oil. Each can had a radius of 3.2 inches and was 15 inches tall. Find the total cubic inches of ol

amid [387]

Step-by-step explanation:

A can is a cylinder.

Volume of a can = Volume of Cylinder

$= \pi {r}^{2} h$

Given Radius = 3.2 inches and height = 15 inches,

Volume of one olive oil can =

$\pi( {3.2}^{2} )(15) \\ = 153.6\pi {in}^{3}$

Volume of 5 olive oil cans = 5 x volume of one olive can

$= 5 \times 153.6\pi \\ = 768\pi {in}^{3}$

I will just leave the answer in terms of pi as I'm not sure if you need to round off your answers.

5 0

3 years ago

How. Many 5s is in 200989

olga_2 [115]

Answer:

40197 these many 5s make up 200985 so 4 are left to make 200989

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

3 years ago

Who can access your credit report?

Maksim231197 [3]

This answer would be B

8 0

3 years ago

Read 2 more answers