Answer:
The correct answer is - 2n = 41 chromosomes.
Explanation:
It is given that the cat has a diploid chromosome number of 38 while the rabbit has a diploid number of 44 chromosomes and if they form a hybrid then their expected chromosome number in somatic cells would be -
Cat (2n=38) produces haploid gametes with 19 chromosomes (n-19).
Rabbit (2n=44) produces haploid gametes with 22 chromosomes(n=22)
19+22= 41 chromosomes in the particular hybrid as half number of chromosomes come from each parent.
10-35%25% based on the table the decrease of the table is 25%25%.Good Luck.
Answer:
a. disruption of mitotic spindle formation.
Explanation:
Vinblastine is a chemotherapeutic drug which is used to restrict cancer cell proliferation. During metaphase, it binds to microtubular proteins which play a very important role in mitotic spindle formation. If spindles will not form then during anaphase, the sister chromatids will not separate and mitosis will not take place. This is how hyper-proliferative cancerous cells are controlled from dividing and cancer is treated using this drug.
Answer:
Electrons are very important in the world of electronics. The very small particles can stream through wires and circuits, creating currents of electricity. The electrons move from negatively charged parts to positively charged ones.
Explanation:
