Question Continuation
What is the probability of people who are
1. mildly obese
2. lean
One study looked at the average, 0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 420 minutes?
Answer:
1. 0.0322
2. 0.9929
Step-by-step explanation:
Given
n = 6
For midly obese people
Mean, u = 371
Standard Deviation, σ = 65
For lean people
Mean, u = 528
Standard Deviation, σ = 108
1. Calculating the probability that people who are mildly obese .
Using z scores for these probabilities.
z = (x - u)/(σ/√n)
Where x = 420
For midly obese people,
z =(420-371)/(65/√6)
z = 1.84653842148270348941026
z = 1.85 --- Approximated
Using the z table, the probability of midly obese people = 1 - p(z=1.85)
= 1 - 0.9678
= 0.0322
2. Calculating the probability that people who are lean
x = 420
z = (420 - 528)/(108/√6)
z = −2.4494897427831780981972
z = -2.45 --- Approximated
Using the z table, the probability of midly obese people = 1 - p(-2.45)
= 1 - 0.0071
= 0.9929
