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2 years ago

Geometry QwQ ////3 ..... help....please....

Mathematics

1 answer:

Ulleksa [173]2 years ago

3 0

Triangle AGB is congruent to Triangle CGB.

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Find the Area of the Polygons:

elena-s [515]

Answer:

480

Step-by-step explanation:

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2 years ago

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Determine the value of k

KATRIN_1 [288]

Answer:

$\displaystyle k = 6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation

Algebra II

Piecewise Functions

Calculus

Limits
Continuity

Step-by-step explanation:

Step 1: Define

Identify

Continuous at x = 2

$\displaystyle f(x) = \left \{ {{2x^2 \ if \ x < 2} \atop {x + k \ if \ x \geq 2}} \right.$

Step 2: Solve for k

Definition of Continuity: $\displaystyle \lim_{x \to 2^+} 2x^2 = \lim_{x \to 2^-} x + k$
Evaluate limits: $\displaystyle 2(2)^2 = 2 + k$
Evaluate exponents: $\displaystyle 2(4) = 2 + k$
Multiply: $\displaystyle 8 = 2 + k$
[Subtraction Property of Equality] Subtract 2 on both sides: $\displaystyle 6 = k$
Rewrite: $\displaystyle k = 6$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Limits - Continuity

Book: College Calculus 10e

4 0

2 years ago

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Middle term of the product of (4x - 1)(2x + 5).

inna [77]

Answer:

Step-by-step explanation:

i know

4 0

2 years ago

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PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME PLEASE HELP!?!?!!?!?!?!?!!?!!?!

Vladimir79 [104]

$\text{Goal: Find } x \text{ such that:} \\ 2^x > 4x + 12$

$2^x > 4x + 12 \\ 2^x > 4(x + 3) \\ 2^{x - 2} > x + 3$

$\text{A lemma: } \\ \text{It is given that: } \\ 2^n > 2n + 1, \text{ } n > 3$
$\text{This can be proven by Mathematical Induction.}$
$\text{Using this lemma, we can manipulate the expression:} \\ 2^{x - 2} > 2(x - 2) + 1 = 2x - 3, \text{ } x > 5 \\ 2\cdot 2^{x - 2} > 2(2x - 3) \\ 2^{x - 1} > 4x - 12 \\ 2^{x - 1} + 24 > 4x + 12$

$\text{Observe the following: } 2^x \text{ will always grow faster than } 2^{x - 1} \\ \text{This implies that } 2^{x} > 2^{x - 1} + 24 > 4x + 12, \text{ given that } x > 5$

$\text{This means that the first month } f(x) > g(x) \text{ is Month 6.}$

8 0

2 years ago

Any help would be appreciated. Thank you

Anestetic [448]

14-3^2 x (-2)
=14-9 x (-2)
=14- (-18)
=32

5 0

2 years ago