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3 years ago

I need help on this math problem.!!

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

7 0

The polygon shown is a pentagon, a five-sided polygon.

There is a formula to find the sum of the measures of the interior angles of any polygon.

S = (n - 2)180

S = sum of the measures of the interior angles

n = number of sides

This is a pentagon, so it has 5 sides. n = 5

We can find the sum, S, of the measures of the angles of any pentagon.

S = (n - 2)180

S = (5 - 2)180

S = 3(180)

S = 540

The sum of the measures of the interior angles of a pentagon is 540 deg.

Now we add all the measures that are shown and subtract from the sum of the measures. That will give us the measure x.

104 + 117 + 100 + 124 = 445

540 - 445 = 95

x = 95

vodomira [7]3 years ago

6 0

x = 95°

the polygon has 5 sides so you do n - 2 which is (number of sides - 2) this gives us 3. now multiply 3 times 180, this gives us 540. now add up all the sides that you know, 104, 117, 100, 124, this is 445 now subract 445 from 540 and that is what gives us 95°

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Ayayayayauauauaua help

Cerrena [4.2K]

Answer:

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Step-by-step explanation:

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3 years ago

A group of friends share 3 1/2 slices of cakes each friend gets half a slice of cake how many friends shared the slices of cake

Mariana [72]

The blanks should be:
2 halves
7 halves
7 friends

This is because 3 and 1/2 is the same as the improper fraction of 7/2.

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2 years ago

Read 2 more answers

NemiM [27]

Answer:

i belive the answer is B

Step-by-step explanation:

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3 years ago

Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with mean 1/0.41/0

lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

$P(t>k)=e^{-\lambda t }=e^{-0.4t}$

(a) the probability that a repair time exceeds 3 hours?

$P(t>3)=e^{-0.4*3}=e^{-1.2}= 0.30$

(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?

The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.

In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

$P(t>10|t>9)=P(t>1)$

$P(k>1)=e^{-0.4*1}=0.67$

6 0

3 years ago

Please help me!!!!!!!

Helen [10]

First we will find the value of x.

To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.

We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.

angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24

Now we can use 24 for x and find the value of angle QRO

angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67

So the answer choice B is the right answer.

Hope this helps :)

6 0

3 years ago