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2 years ago

3 ½ x 2/5 *

Mathematics

1 answer:

ki77a [65]2 years ago

4 0

Answer:

Step-by-step explanation:

$3\frac{1}{2}=\frac{(3*2)+1}{2}=\frac{7}{2}\\\\\\3\frac{1}{2}*\frac{2}{5}=\frac{7}{2}*\frac{2}{5}=\frac{14}{10}$

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A website requires a 7 digit password. How many different passwords can be made using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and

olga_2 [115]

B because 10 x 7 = 70

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3 years ago

Simplify: <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%5E%7B3%7D-7%5Ccdot3%5E%7B4%7D-2%5E%7B5%7D%5Ccdot9%7D%7B%5Cleft%281-

klio [65]

Answer:

Simplifed:

$\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3}}$

$\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3} } \\ \frac{216 - 567 -288 }{ { - 7}^{3} + {7}^{3} } \\ \frac{ - 639}{0}$

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2 years ago

In the figure below, B is between A and C, and C is between B and D. If AC=9, BD=10, and BC-2, find AD

ehidna [41]

Considering the situation described in the problem, the length of segment AD is of: 17 units.

<h3>How to find the length of segment AD?</h3>

From the situation described in the problem, segment AD is divided into three parts:

Part AB.

Part BC.

Part CD.

Then, the length of segment AD is:

AD = AB + BC + CD.

We have that AC = 9, hence:

AB + BC = 9.

We also have that BD = 10, then:

BC + CD = 10.

Since BC = 2, we have that:

AB + BC = 9 -> AB + 2 = 9 -> AB = 7.

BC + CD = 10 -> 2 + CD = 10 -> CD = 8.

Then the length of segment AD is given as follows:

AD = AB + BC + CD = 7 + 2 + 8 = 17.

More can be learned about the length of segments at brainly.com/question/7694028

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1 year ago

The amount of oil used by a ship traveling at a uniform speed varies jointly with the distance and the square of the speed. The

frosja888 [35]

Answer:

Step-by-step explanation:

Joint variation has the equation

y = kxz

k is the constant of variation and needs to be solved for using the initial conditions, then filled in later to another equation related to the given info to solve for something else. We are given y = amount of oil used, x = distance traveled, z-squared is the speed. Our equation looks like this, to be exact:

$y=kxz^2$