Answer:
x = 9º
∠B = 40º
Step-by-step explanation:
5x-5º = 3x+13º
<em>[add 5 to both sides]</em>
5x = 3x+18º
<em>[subtract 3x from both sides]</em>
2x = 18º
<em>[divide each side by 2]</em>
x = 9º
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3x+13º = 3(9º)+13º=27º+13º = 40º
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
Step-by-step explanation:
6x - 2y = -4
y= 3x + 2
We see that y = 3x + 2 so we can use that value of Y everytime we see i in the other equation.
6x - 2(3x +2) = -4
Now usually we'd we simply solve for X.
6x - 6x -4 = -4
This clearly does not work as we cannot get rid of X
Therefore, this system of equations has no solution we can find through substitution
Answer:
trapezium................
Answer:

Step-by-step explanation:

Hope this will help you :))