Answer:
............................
Step-by-step explanation:
Answer:
0.1151
Step-by-step explanation:
Given that a laptop company claims up to 10.1 hours of wireless web usage for its newest laptop battery life. However, reviews on this laptop shows many complaints about low battery life. A survey on battery life reported by customers shows that it follows a normal distribution with mean 9.5 hours and standard deviation 30 minutes.
If X is the battery life then X is N(9.5, 0.5)
(we convert into one unit for calculations purpose here hours)
a) the probability that the battery life is at least 10.1 hours
=
we get the probability that the battery life is at least 10.1 hours is 0.1151
Answer:
13) 10b^2a^4
14) -5y^3+35y^2-10y
14.4, if my calculator was correct
Answer:
330
Step-by-step explanation:
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