Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
120 degrees is the answer
Answer:
x = 47°
Step-by-step explanation:
m∠DPB + ∠BPC = 180° (Definition of a straight line)
Plug in the corresponding numbers and variables to the corresponding places:
x + 133 = 180
Isolate the variable, x. Subtract 133 from both sides:
x + 133 (-133) = 180 (-133)
x = 180 - 133
x = 47
47° is your answer.
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I don't see a question here, but I think your asking how many sixth graders will attend. The answer is 24.
Answer:
The rectangle divided in 2 equal parts
Step-by-step explanation: