All categories

3 years ago

I need to solve the whole thing

Mathematics

1 answer:

kipiarov [429]3 years ago

4 0

1.) 40, 2.) 8, 3.) 18, 4.) 15, 8.) 12, 9.) 30, 10.) 72, 11.) 36

You might be interested in

What is 5/7 of 7/10??????

7nadin3 [17]

Just multiply them together
5/7 * 7/10 = 35/70 = 1/2

5 0

2 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

6 0

2 years ago

A bowler knocks at least 6 pins 70% of the time.Out of 200 rolls, how many times can you predict the bowler will knock down at l

ankoles [38]

The bowler will hit 6 pins 140 times because 70% of 200 is 140

6 0

3 years ago

Anyone know the answer to this question?

denpristay [2]

Answer:

sorry i dont know how to solve this

Step-by-step explanation:

5 0

3 years ago

16j + -6j + -12j = -10

nordsb [41]

Answer:

j = 5

Step-by-step explanation:

16j + -6j + -12j = -10

Combine like terms

10j -12j = -10

-2j = -10

Divide by -2

-2j/-2 = -10/-2

j = 5

8 0

2 years ago

Read 2 more answers