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Mamont248 [21]
3 years ago
15

What effect does distance have on the force of gravity?

Physics
2 answers:
Bess [88]3 years ago
5 0

Answer:

The answer is increasing the distance between two objects decreases the gravitational force. which is C

Andreyy893 years ago
3 0

Answer:

C - Increasing the distance between two objects decreases the gravitational force.

Explanation:

The force of gravity depends on the objects' mass (m₁ and m₂) and distance between the objects' centers of gravity (r), as described by Newton's law of gravitation:

F = G m₁ m₂ / r²

Increasing the distance r decreases the gravitational force F.

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What happens when infrared hits a shiny surface
saw5 [17]
Will reflect ........
3 0
4 years ago
An old manuscript reveals that a landowner in the time of King Arthur held 3.00 acres of plowed land plus a livestock area of 25
iragen [17]

Answer:

(a) Total area is 14.5 roods

(b) Total area is 14674.522 square meters

Explanation:

Area occupied by land = 3 acres

1 acre = 40 perches by 4 perches = 160 square perches

3 acres = 3×160 = 480 square perches

Area occupied by livestock = 25 perches by 4 perches = 100 square perches

Total area = 480 + 100 = 580 square perches

1 rood = 4 perches by 1 perch = 4 square perches

580 square perches = 580/4 = 14.5 roods

(b) Total area = 580 square perches

1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters

580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters

8 0
3 years ago
Enter the expression 2gΔym−−−−−√, where Δ is the uppercase Greek letter Delta.
Anon25 [30]
This doesnt make sense. 2g<span>Δym is simply an equation. </span>
5 0
3 years ago
how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?
nlexa [21]
Could you supply u with some answer choices please?
8 0
4 years ago
Pikes Peak near Denver, Colorado, has an elevation of 14,110 ft. Calculate the pressure at this elevation using three different
kramer

Answer:

a) P = 1240 lb/ft^2

b) P = 1040 lb/ft^2

c) P = 1270 lb/ft^2

Explanation:

Given:

- P_a = 2216.2 lb/ft^2

- β = 0.00357 R/ft

- g = 32.174 ft/s^2

- T_a = 518.7 R

- R = 1716 ft-lb / slug-R

- γ = 0.07647 lb/ft^3

- h = 14,110 ft

Find:

(a) Determine the pressure at this elevation using the standard atmosphere equation.

(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.

(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.

Solution:

- The standard atmospheric equation is expressed as:

                           P = P_a* ( 1 - βh/T_a)^(g / R*β)

                          (g / R*β) = 32.174 / 1716*0.0035 = 5.252

                            P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252

                            P = 1240 lb/ft^2

- The air density method which is expressed as:

                            P = P_a - γ*h

                            P = 2116.2 - 0.07647*14,110

                            P = 1040 lb/ft^2

- Using constant temperature ideal gas approximation:

                            P = P_a* e^ ( -g*h / R*T_a )

                            P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )

                            P = 1270 lb/ft^2

6 0
3 years ago
Read 2 more answers
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