The correct answer is:
2u-v=7(5i-3j)
Therefore, 5, and 3 go inside the box.
Let number of plastic containers collected by fourth grade= x
Then number of plastic containers collected by fifth grade students=x-216
OR
If number of plastic container collected by fifth grade is y
then number of plastic container collected by fourth grade=y+216
So, we can write it as follows
⇒ number of plastic containers collected by fourth grade= number of plastic containers collected by fifth grade +216
Answer:
-¹²/₅
Step-by-step explanation:
Let cos a = -⁵/₁₃
Then tan a = sin a/cos a
= [√(1 - cos²a)]/cos a
= {√[1 - (-⁵/₁₃)²]}/(-⁵/₁₃)
= -[√(1 - ²⁵/₁₆₉)] × ¹³/₅
= -[(√(¹⁴⁴/₁₆₉ )] × ¹³/₅
= -¹²/₁₃ × ¹³/₅
= -¹²/₅
tan(arccos (-⁵/₁₃)) = -¹²/₅
The diagram shows the 2nd quadrant of a circle with radius 13, cos a = -⁵/₁₃, and tan a = ¹²/₍₋₅₎ = -¹²/₅.
Answer:
Diameter 16, radius 7, circumference 37.68, diameter 8
Step-by-step explanation:
Largest area will be in a circle with the largest radius. So let's find all radii.
d = 8, so r = 4;
r = 7;
circumference = 2pi*r = 37. 68, so r = 6
diameter 18, so r = 8
Step-by-step explanation:
equation of a line = y-y1=m(x-x1)
but we have to find the slope
so slope=<u>y</u><u>2</u><u>-</u><u>y</u><u>1</u><u> </u><u> </u><u> </u><u> </u> = -<u>7-5</u>
x2-x1. 3--3
<u>-12</u>
6
<u>-2</u>
1. =-2
y-5=-2(x-3)
y-5=-2x+6
y=-2x+6-5
y=2x+1
