Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer: (4, 3)
Step-by-step explanation:
The formula for coordinate of the mid point is given as :
Mid point = (
, 
)
= 9
= -1
= 9
= -3
Substituting the values into the formula , we have :
Mid-point = (
, 
)
Mid-point = ( 
, 
)
Mid - point = ( 4 , 3)
Answer:
y=1/2x+2
Step-by-step explanation:
Answer:
Step-by-step explanation:
The horizontal asymtote is when there are no solutions for x, so it is when y = -10.
This is because when y = -10, 0.8^x must be 0, but this is impossible. You can test this by trying 4^x/5^x. It will get super small, but never 0.
x^2-9x-6=0
Use the quadratic formula to get (9+sqrt(105))/2 or (9-sqrt(105))/2
