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dalvyx [7]
3 years ago
12

;))))))))))))))))))))))))))))))))))))))))))))))))))))))))

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Outcome:

Reported

Reason:

Sorry, but this isn't a question. It violates the Community Guidelines, and it isn't the purpose of Brainly. The purpose of brainly is to help people with homework or questions they have and rewards people who help other people. This question is giving free points to people regardless if they were a help or not.

adelina 88 [10]3 years ago
6 0

Answer:

;)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))

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What is the constant of proportionality of a graph if x equals 3 and y equals 90?
solmaris [256]
y = kx

'k' is the constant of proportionality, or otherwise known as constant of variation. 

y = 90
x = 3

90 = k(3)
90 = 3k
3k/3 = 90/3
k = 30

The constant of proportionality is 30. 
6 0
3 years ago
Geometryyy pls help ty
zimovet [89]
16-~7 make sure to leave the power 5 out
3 0
3 years ago
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Please help on these questions​
Arada [10]

Answer:

6) 9216π

8) 24

Step-by-step explanation:

6)

V= 2/3πr³

   r = 48/2 = 24

V = 2/3π24³

V = 9216π

8)

V = 4/3πr³

2304π = 4/3πr³

r³= (2304π)/4/3π

r³= 1728

\sqrt[3]{r^3} =\sqrt[3]{1728}

r = 12

D = 2r

D = 2 x 12 = 24

8 0
3 years ago
What is the 30th term of the arithmetic series 4, 7, 10, … ?
Irina18 [472]
a_1=4;\ a_2=7;\ a_3=10\\\\d=a_2-a_1\to d=7-4=3\\\\a_n=a_1+(n-1)d\to a_n=4+(n-1)\cdot3=4+3n-3=3n+1\\\\\boxed{a_n=3n+1}\\\\a_{30}=3\cdot30+1=90+1=91\\\\Answer:\boxed{a_{30}=91}
3 0
4 years ago
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Given the function:
anyanavicka [17]
You are correct. The answer is choice D

The only way for g(x) to be differentiable at x = 0 is for two things to happen
(1) g(x) is continuous at x = 0
(2) g ' (x) is continuous at x = 0

To satisfy property (1) above, the value of b must be 1. This can be found by plugging x = 0 into each piece of the piecewise function and solving for b. 

So the piecewise function becomes
g(x) = \begin{cases}x+1 \ \text{ if } \ x \ < \ 0\\ \cos(x) \text{ if } \ x \ge 0\end{cases}
after plugging in b = 1

--------------------------------

Now differentiate each piece with respect to x to get
g'(x) = \begin{cases}1 \ \text{ if } \ x \ < \ 0\\ -\sin(x) \text{ if } \ x \ge 0\end{cases}
The first piece of g ' (x) is always going to be equal to 1. The second piece is equal to zero when x = 0
Because -sin(x) = -sin(0) = 0

So there's this disconnect on g ' (x) meaning its not continuous

Therefore, the value b = 1 will not work. 

So there are no values of b that work to satisfy property (1) and property (2) mentioned at the top. 

5 0
3 years ago
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