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podryga [215]
3 years ago
8

Please help me and I’ll give you brainiest!!!!!!!!!

Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

137

Step-by-step explanation:

because you have to add the nubers

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Jasmine sells bracelets at a local jewelry store in South Dekalb Mall. She has 1,190 purple beads and 2,125 pink beads. Each bra
jeka57 [31]

Answer:

39

Step-by-step explanation:

1190 + 2125 = 3315 (number of beads)

3315/85 = 36 (number of bracelets jasmine can make)

8 0
3 years ago
A ________ exists between two variables when the values of one variable are somehow associated with the values of the other vari
motikmotik
Correlation would be the correct answer
8 0
3 years ago
Use the Properties of Equality to solve each equation.
castortr0y [4]
The answer is -25

All you have to do is add -6-9 which equals -25 because “same signs add(+) and keep” “different signs subtract(-)” but “add” means positive number and “subtract” means negative number. Since they are different signs a (+) and a (-) you subtract it.

Hope this helps!
6 0
1 year ago
The length of a rectangle is 3 times twice the width. The perimeter is 36. What are the side lengths?
Svetllana [295]

Answer & Explanation:

For this question, you need to figure out the length and the width because the area is directly related to them (A = l*w).

What we do know is that the perimeter is 36 inches. Since the perimeter is equal to P = 2l + 2w, we can say:

P = 36 = 2(3 + 2w) + 2(w), where the length l is 3 + 2w

Solve for w first, then solve for l. Use these values to find the area.

Pls, choose me as brainliest!

8 0
2 years ago
What is a solution to 4x+6<(with a line under it ) 18
JulsSmile [24]

Answer:

\textbf{$x \in (-\infty, 3] $}\\

Step-by-step explanation:

\textup{Given:}\\$ 4x + 6 $\textup{Subtracting $6$ from both the sides }\\$ 4x \leq 18 - 6 \hspace{5mm} (=12) $\\\textup{Dividing by $4$ on both the sides: \hspace{15mm} [Note that the sign of the inequality changes only when we divide it by a negative number]}\\$$ x \leq 3 $$\\\textup{$x$ can be any real number less than or equal to 3.}\\$ \iff x \in R^- \cup \{a : 0 \leq a \leq 3\} $

7 0
3 years ago
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