Answer:
Explanation:
Given a mass spring system
At t = 0.1s, the positions is at x=8cm
x(0.1) = 8cm = 0.08m
Spring constant k=16N/m
Mass attached m = 4kg
Amplitude of oscialltion A=10cm = 0.1m
The angular frequency can be calculated using
w = √k/m
Where k is spring constant in N/m
m is mass attached object to the spring in kg
w = √16/4 = √4
w = 2rad/s.
Generally, the equation of a spring is given as
x = ACos(wt+Φ)
Where,
A is amplitude in metre
w is angular frequency in rad/sec
Φ is phase in radian
x(t) = 0.1Cos(2t + Φ)
At t=0.1 x = 0.08
0.08 = 0.1Cos(0.2+Φ)
Cos(0.2+Φ) = 0.08/0.1
Cos(0.2+Φ) = 0.8
0.2+Φ = ArcCos(0.8), note angle in radiant
0.2+Φ = 0.644
Φ = 0.644 — 0.2
Φ = 0.444 rad.
The phase of the SHM is 0.444rad
The answer is E = 0.44 rad
Answer: 0.9264 kg
Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.
The volume is 6cm*4cm*2cm = 48 cm^3 (cc).
Density of Au is 19.3 g/cc
Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au
1 kg = 1,000 g
(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs
At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).
50.5cm= 0.00505hm
Hope this helps!
I think so it's a beta particles which is a high speed electrons
Answer:
The acceleration of a rock thrown straight upward on the way up, at the top of its flight and on the way down is called gravity, and it's denoted by the letter g.
Gravity change vary depending on the position on Earth or the planet that you are studying
Usually on earth we use
Explanation:
<u>If we analyze </u><u>Newton's second law</u>
<u>Then we have the force that is caused by the </u><u>weight</u><u> of the rock</u>
So, we have that