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aev [14]
3 years ago
9

Question 1 Water: Start with the Water tab. Note that light areas represent places where the water is high (crests). Dark areas

represent low points (troughs). The water drops should already be dripping from the faucet. You can inerease their frequency and amplitude by using the Frequency and Amplitude slider. Using the controls on the far right, you can add measuring tools, add wall, add another faucet, or insert a single-slit or tw0-slit barrier. Part A What kind of wave patterns do you observe in the sink in the top view? I Part B Click on the Show Graph button in the top right corner of the window. The graph shows the moving water level, which is the actual amplitude of the waves. What general mathematical graph function does this look like? What pattern do you observe in the amplitude of these waves? Provide a hypothesis to explain this pattern in the amplitude. I Part C What happens when you increase the frequency of the water drops? What happens to the wavelength of the waves on the surface of water? PLZ ANSWER ALL FOR BRAINLIEST​
Physics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

Looks like a cosine function graph. The wave pattern is transversal waves . The faster the amplitude the higher the wave. The force of the drop hitting the water pushes the water down and out causing waves  If the water hits from a higher amplitude the waves raise bigger . When you increase the frequency of the water drops the waves move faster but no bigger.  When you increase the frequency of the water drops the wave ripples faster .

Explanation:

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Aleks [24]

1) 29.4 N

The force of gravity between two objects is given by:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M and m are the masses of the two objects

r is the separation between the centres of mass of the two objects

In this problem, we have

M=5.97\cdot 10^{24} kg (mass of the Earth)

m=3.0 kg (mass of the box)

r=R=6.37\cdot 10^6 m (Earth's radius, which is also the distance between the centres of mass of the two objects, since the box is located at Earth's surface)

Substituting into the equation, we find F:

F=\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24})(3.0)}{(6.37\cdot 10^6)^2}=29.4 N

2) g=9.8 m/s^2

Let's now calculate the ratio F/m. We have:

F = 29.4 N

m = 3.0 kg

Subsituting, we find

\frac{F}{m}=\frac{29.4}{3.0}=9.8 N/kg = 9.8 m/s^2

This is called acceleration of gravity, and it is the acceleration at which every object falls near the Earth's surface. It is indicated with the symbol g.

We can prove that this is the acceleration of the object: in fact, according to Newton's second law,

F=ma

where a is the acceleration of the object. Re-arranging,

a=\frac{F}{m}

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Sholpan [36]

Answer:

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Explanation:

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