You didn't show anything, but more energy would affect enzyme activity.
Answer: DF508 mutation. A Genetic, Hereditary, Autosomal and Recessive Mutation.
Explanation:
Cystic fibrosis (CF) is a recessive autosomal lethal disease, it is most common on Caucasoid populations. Its diagnosis is suggested by the clinical features of chronic obstructive pulmonary disease, persistent pulmonary colonization (particularly with mucoid Pseudomonas strains), meconium ileus, pancreatic insufficiency with or familiarity history of the disease. The FC gene is large, with about 250 Kb of genomic DNA, 27 exons representing about 5% of genomic DNA; encodes a 6.5 kb transcribed mRNA. This mRNA is transcribed into a protein of 1480 amino acid called CFTR (Regulator Transmembrane Conductance Cystic Fibrosis). When a three-base pair deletion, adenosine-thymine-thymine (ATT) identified in the CFTR gene, exon 10, it results in the loss of a single amino acid phenylalanine at position 508 of the protein. This mutation is called DF508; “D” stands for deletion and “F” for phenylalanine amino acid.
Answer:
no one is that I can get it to you tomorrow at the same time ago i used to
Explanation:
no one is that I can get it to you tomorrow at the same time ago i used to
<span>The san Andreas fault
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In the calvin cycle, glyceraldehyde-3-phosphate (G3P) is first and foremost responsible for making glucose. To make one G3P molecule, you need three turns of the calvin cycle. In the GP3 molecule, you hade 3 fixed carbon atoms. So to make a six-carbon glucose molecule, you need two GP3 molecules. Therefore it takes 6 turns of the calvin cycle (photosynthesis) to make a glucose molecule.