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kolbaska11 [484]
4 years ago
15

A generator can be made using the component of Earth’s magnetic field that is parallel to Earth’s surface. A 140-turn square wir

e coil with an area of 4.30 ×10−2 m2 is mounted on a shaft so that the cross-sectional area of the coil is perpendicular to the ground. The shaft then rotates with a frequency of 21.4 Hz. The horizontal component of the Earth’s magnetic field at the location of the loop is 3.00 ×10−5 T.
Calculate the maximum emf induced in the coil by Earth's magnetic field.
Physics
1 answer:
Katen [24]4 years ago
7 0

Answer:

The maximum induced emf is    \epsilon = 0.024 V

Explanation:

From the question we are told that

   The number of turns is N = 140 \ turns

    The area of the square wire coil is  A = 4.30 * 10^{-2}m^2

    The frequency of rotation is  f = 21.4 Hz

    The earth magnetic field at that location is  B = 3.00 *10^{-5} T

The  induced emf is mathematically represented as

         \epsilon = N \ B \ A \ w sin(wt)

At the maximum

       sin (wt) = 1

So

         \epsilon = N \ B \ A \ w

Where

    w is the angular velocity which is mathematically represented as

          w  =2 \pi f

Substituting values

             w = 2 * 3.142 * 21.4

            w = 134.5 rad/sec

The maximum induced emf is  

          \epsilon = 140 * 3.00*10^{-5}  * (4.30 *10^{-2}) * (134.5)

           \epsilon = 0.024 V

     

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