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STALIN [3.7K]
3 years ago
6

If an ant is starting from 0 radians, and travels all the way to 4.5 radians in 18 seconds, what is angular velocity? If the sam

e ant then slows down back to 0 rad/s in 3 seconds what is its angular acceleration?
Physics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

  • Angular velocity is 0.25 rad/s
  • Angular acceleration is 0.017 rad/s²

Explanation:

Given;

initial angular displacement, θ₁ = 0 radians

final angular displacement, θ₂ = 4.5 radians

Angular velocity is calculated as;

\omega = \frac{\delta \theta}{\delta t}= \frac{4.5 -0}{18}  \\\\\omega = 0.25 \ rad/s

Angular acceleration is calculated as;

\alpha = \frac{\delta \omega}{\delta t} = \frac{\omega _f - \omega_i}{t_2 -t_1}

where;

\omega_f is the final angular velocity = 0 rad/s

\omega _i is the initial angular velocity = 0.25 rad/s

t₂ is the final time of the motion = 3 seconds

t₁ is the initial time of the motion = 18 seconds

\alpha =\frac{\omega _f - \omega_i}{t_2 -t_1} \\\\\alpha = \frac{0 - 0.25}{3-18} \\\\\alpha = 0.017 \ rad/s^2

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Answer:

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Explanation:

Step 1: Data given

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Formula: R = Rref(1 + α(T-Tref))

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⇒with R = resistance at end temperature = 58Ω

⇒with Rref = resistance at reference temperature =  50 Ω

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T = (58/50) - 1 )/ 0.00394 + 20

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