Answer:
Its mechanical energy is the same.
Explanation:
If forces are only conservative, the mechanical energy will be the same.
It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.
If we just have mechanical energy not geting transformed we have:
Em=K+U
Em: Mechanical energy
K: Kinetic energý
U: Potential energy
Then if Kinetic energy decreases 10J, Potential energy will grow up 10J to keep the same amount of mechanical energy.
If you look at the picture you will see how, but the answer is 0.5 Hz.
To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that
F = ma
Where,
m = mass
a = Acceleration (Gravitational acceleration when there is action over the object of the earth)
Torque, as we know, is the force applied at a certain distance, that is,

Where
F= Force
d = Distance
Our values are given as,



Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say






Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is 
Answer:
Explanation:
let the ball is thrown vertically downwards with velocity u.
So, initial velocity, = - u (downwards)
acceleration = - g (downwards)
let the velocity is v after time t.
use first equation of motion
v = u + at
- v = - u - gt
v = u + gt
So, it is a straight line having slope g and y intersept is u.
The graph I shows the velocity - time graph.
Now the value of acceleration remains constant and it is equal to - 9.8 m/s^2.
So, acceleration time graph is a starigh line parallel to time axis having slope zero.
the graph II shows the acceleration - time graph.
Use III equation of motion to find the final speed in terms height.

And the time is
v = u + gt
