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Svetlanka [38]
2 years ago
12

Does someone mind helping me with this question? Thank you!

Mathematics
2 answers:
marta [7]2 years ago
6 0

Answer:

I dont mind :D These were my favorite! They are actually really simple. Dont overthink it. It even gave you a hint!

It says a^2 + b^2 = c^2

We can substitute what we do have which is a = 10 and c = 15

10^2 + b^2 = 15^2

Now we square it

100 + b^2 = 225

Next, all we have to do is subtract the 100 from our answer so 225-100 which is 125, so b has to be 125!!! Because 125 + 100 is 225 :D

Step-by-step explanation:

sammy [17]2 years ago
3 0
<h3>Given:</h3>
  • Hypotenuse ( c )= 15
  • Side 1 ( a )= 10
<h3>To find:</h3>

The length of "b" using Pythagoras Theorem.

<h3>Solution:</h3>

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{10}^{2}  +  {b}^{2}  =  {15}^{2}

b =  {15}^{2}  -  {10}^{2}

{b}^{2}  = 125

b =  \sqrt{125}

b = 11.18033989

b = 11.2 \: (nearest \: tenth)

<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>"</u><u>b"</u><u> </u><u>is</u><u> </u><u>11.2</u>

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Answer:

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Step-by-step explanation:

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3) 2z = 24

4) z = 12

5) 3(12) + 8 = 44

For EG:

1) 2w + 22 = 4w + 4

2) 2w = 4w - 18

3) -2w = -18

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2 years ago
Jenna is drawing a sketch of her room. The room is 15 feet long by 12 feet wide. The
SOVA2 [1]

Answer:

4 inches

Step-by-step explanation:

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Scale dimensions:

Length = 5 inches

Width = x inches

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3 0
3 years ago
Condense the following logarithm: <br><img src="https://tex.z-dn.net/?f=5%20log_%7B4%7D%28a%29%20%20-%206%20log_%7B4%7D%28b%29%2
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2 years ago
Jacob made a circle-shaped poster for his geometry class.
krok68 [10]
<span>circumference is L=2\pi r
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The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th
Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

A=\frac{1}{2} (b_{1} +b_{2} )h

where, h be the height of the trapezoid

b_{1} be the shorter base

b_{2} be the longer base

As per the given problem,

b_{2}=b_{1}  +6

Now,

Putting, A=72, b_{2}=b_{1}+6 and h=6 we get,

\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72

or, b_{1}+b_{1}+6 = \frac{(72)(2)}{6}

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or, b_{1}= \frac{18}{2}

or, b_{1}=9

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The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

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