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yKpoI14uk [10]
1 year ago
14

In experiments in which participants manually tracked a complex pattern that consisted of two segments that were random patterns

on every trial and one segment that was the same every trial, the results showed that the participants improved
more on the repeated segment than the two random segments, and reported they were not aware that one segment was the same on every trial.
Mathematics
1 answer:
PilotLPTM [1.2K]1 year ago
5 0

For the given experiments , participants concluded that complexity is more on the random patterns on every trials compare to  one segment that was same for every trial.

As given in the question,

Steps for the experiment where participants manually tracked a complex pattern which consists of two segments are as follow:

In first case : One segment consists of random patterns on every trial that is on every new trial there is new random pattern which participant has to follow.

In second case : Another segment consists of same pattern on every new trial.

After conducting experiment reports conclude that repeated segment with the same pattern present more improved result compare to random patterns. As participants were aware of the same segment on each new trial.

Therefore, given experiments of participants proves the complexity is more on the random patterns on every trials compare to one segment  same for every trial.

Learn more about experiment here

brainly.com/question/11256472

#SPJ4

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Lera25 [3.4K]
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1/5r = 3/4
Multiply 5 on both sides of the equation.

r = 15/4

The relay was 15/4 of a mile or 3 3/4 of a mile.

2.) No, it is not because the sum of the digits are not divisible by 3.

Hope this helps! :)
7 0
2 years ago
Read 2 more answers
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Fed [463]

Answer: 4 bags

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2 years ago
Which of the following ratios are equivalent to 6:9? Choose all that apply
kipiarov [429]

Answer:

Dear we can't give you an answer without the options.

Step-by-step explanation:

ratios that are equivalent to 6:9 are however

2:3, 6:9, 12:18, 18:27, 24:36, 30:45 I believe.

5 0
3 years ago
Write an explicit formula for a^n the nth term of the sequence 1,3,9....
frutty [35]

Answer:

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Step-by-step explanation:

The n-th term of a geometric sequence with first term a1 and common ratio r is given by ...

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Your sequence has first term 1 and ratio r=3, so the sequence is given by ...

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_____

<em>Comment on sequences and series</em>

The sequences we commonly study are "arithmetic" and "geometric." Each of these has an explicit formula for the n-th term, based on the first term and the common difference or ratio. Similarly, each series (sum of terms of a sequence) also has a formula. That's 4 formulas to keep track of; not difficult. One of them, the formula for the n-th term of a geometric sequence, is shown above.

7 0
3 years ago
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Hunter-Best [27]

Answer:

0.020

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Step-by-step explanation:

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<u><em>Hope this helps, and stay safe!! :))))</em></u>

4 0
2 years ago
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