Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
To solve both of these expressions, we want to add or subtract from left to right.
For the first one, we can rewrite it as:
8-6-9
=2-9
=-7
The second one we can rewrite as:
5-7+9+8-4
=-2+9+8-4
=7+8-4
=15-4
=11
Answer:
The area of the smaller triangle is 75.
Step-by-step explanation:
Here, the ratio of the sides of the similar triangle are 5 : 6
The area if the larger triangle = 108
let us assume that the area of the smaller triangle = m
By the Theorem:
In two similar triangles, the ratio of the areas of similar triangles is the square of the ratio of their sides.
Similarly, here
 ^2](https://tex.z-dn.net/?f=%5Btex%5D%28%5Cfrac%7B5%7D%7B6%7D%29%20%5E2)
= \frac{m}{108}[/tex]
⇒
or, 
⇒ m = 75
Hence, the area of the smaller triangle is 75.
