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yKpoI14uk [10]
1 year ago
14

In experiments in which participants manually tracked a complex pattern that consisted of two segments that were random patterns

on every trial and one segment that was the same every trial, the results showed that the participants improved
more on the repeated segment than the two random segments, and reported they were not aware that one segment was the same on every trial.
Mathematics
1 answer:
PilotLPTM [1.2K]1 year ago
5 0

For the given experiments , participants concluded that complexity is more on the random patterns on every trials compare to  one segment that was same for every trial.

As given in the question,

Steps for the experiment where participants manually tracked a complex pattern which consists of two segments are as follow:

In first case : One segment consists of random patterns on every trial that is on every new trial there is new random pattern which participant has to follow.

In second case : Another segment consists of same pattern on every new trial.

After conducting experiment reports conclude that repeated segment with the same pattern present more improved result compare to random patterns. As participants were aware of the same segment on each new trial.

Therefore, given experiments of participants proves the complexity is more on the random patterns on every trials compare to one segment  same for every trial.

Learn more about experiment here

brainly.com/question/11256472

#SPJ4

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Julli [10]

Answer:

Part 1) see the explanation

Part 2) see the explanation

Part 3) see the explanation

Part 4) see the explanation

Step-by-step explanation:

<u><em>The question in English is</em></u>

Read the situations and do the following with each one:

Write down the magnitudes involved

Write which magnitude is the independent variable and which is the dependent variable

It represents the function that describes the situation

SITUATIONS:

1) A machine prints 840 pages every 30 minutes.

2) An elevator takes 6 seconds to go up two floors.

3) A company rents a car at S/ 480 for 12 days.

4) 10 kilograms of papaya cost S/ 35

Part 1) we have

A machine prints 840 pages every 30 minutes

Let

x ----> the time in minutes (represent the variable independent or input value)

y ---> the number of pages that the machine print (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=840\ pages\\x=30\ minutes

substitute

 k=\frac{840}{30}=28\ pages/minute

The linear equation is

y=28x

Part 2) we have

An elevator takes 6 seconds to go up two floors.

Let

x ----> the time in seconds (represent the variable independent or input value)

y ---> the number of floors (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=2\ floors\\x=6\ seconds

substitute

 k=\frac{2}{6}=\frac{1}{3}\ floors/second

The linear equation is

y=\frac{1}{3}x

Part 3) we have

A company rents a car at S/ 480 for 12 days.

Let

x ----> the number of days (represent the variable independent or input value)

y ---> the cost of rent a car (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$480\\x=12\ days

substitute

 k=\frac{480}{12}=\$40\ per\ day

The linear equation is

y=40x

Part 4) we have

10 kilograms of papaya cost S/ 35

Let

x ----> the kilograms of papaya (represent the variable independent or input value)

y ---> the cost  (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

 k=\frac{y}{x}

we have

y=\$35\\x=10\ kg

substitute

 k=\frac{35}{10}=\$3.5\ per\ kg

The linear equation is

y=3.5x

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2 years ago
How do I solve this?
bogdanovich [222]

Answer:

<h2>5(x + 7)²</h2>

Step-by-step explanation:

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zubka84 [21]

Answer:

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Step-by-step explanation:

The given linear system has a equation which is not in echelon form. The echelon is a system which divides the data into rigid hierarchal groups. The given linear equation in not in echelon form as the leading variables are increased from top to bottom indicating descending stair step pattern.

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3 years ago
26 push-ups in 2 minutes
OlgaM077 [116]

Answer:

13 per minute

Step-by-step explanation:

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