Answer:
<em>Heat rejected to cold body = 3.81 kJ</em>
Explanation:
Temperature of hot thermal reservoir Th = 1600 K
Temperature of cold thermal reservoir Tc = 400 K
<em>efficiency of the Carnot's engine = 1 - </em>
<em> </em>
eff. of the Carnot's engine = 1 - 
eff = 1 - 0.25 = 0.75
<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>
work done by heat engine = 2 kJ
<em>eff. of heat engine is gotten as = W/Q</em>
where W = work done by heat engine
Q = heat rejected by heat engine to lower temperature reservoir
from the equation, we can derive that
heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>
Answer:
During film condensation on a vertical plate, heat flux at the top will be higher since the thickness of the film at the top, and thus its thermal resistance, is lower.
Explanation:
https://www.docsity.com/pt/cengel-solution-heat-and-mass-transfer-2th-ed-heat-chap10-034/4868218/
https://arc.aiaa.org/doi/pdf/10.2514/1.43136
https://arxiv.org/ftp/arxiv/papers/1402/1402.5018.pdf
Answer:
pls mark me as brainliest
Explanation:
Answer: 7.36 mA
The question did not include the output to be produced. However, below are the outputs.
My age is 21
Twice my age is 42
Three times my age is 63
ANSWER:
public class NewClasss{
public static void main(String[] args) {
int x,y,z;
x = 21;
y = 2*x;
z=3*x;
System.out.println("My age is " + x);
System.out.println("twice my age is " + y);
System.out.println("three times my age is " + z);
}
}
Answer:
Change in entropy S = 0.061
Second law of thermodynamics is satisfied since there is an increase in entropy
Explanation:
Heat Q = 300 kW
T2 = 24°C = 297 K
T1 = 7°C = 280 K
Change in entropy =
S = Q(1/T1 - 1/T2)
= 300(1/280 - 1/297) = 0.061
There is a positive increase in entropy so the second law is satisfied.
