ITS FOR DRIVERS ED!!
2 answers:
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Explanation:
R total = 4.25 ohm
I total = Vt/Rt
I total= 17/4.25= 4 A
Ix= 600 mA
Answer:
See the attached picture for answer.
Explanation:
See the attached picture for explanation.
Answer:
a) The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump is 245.175 kilopascals.
Explanation:
a) Let suppose that pump works at steady state. The mass flow rate of the water (), in kilograms per second, is determined by following formula:
(1)
Where:
- Pump power, in watts.
- Efficiency, no unit.
- Gravitational acceleration, in meters per square second.
- Hydrostatic column, in meters.
If we know that ,
,
and
, then the mass flow rate of water is:
The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump (), in pascals, is determined by this equation:
(2)
Where is the density of water, in kilograms per cubic meter.
If we know that ,
and
, then the pressure difference is:
The pressure difference across the pump is 245.175 kilopascals.
Answer:
See explaination
Explanation:
Code;
import java.util.Scanner;
public class NumberPattern {
public static int x, count;
public static void printNumPattern(int num1, int num2) {
if (num1 > 0 && x == 0) {
System.out.print(num1 + " ");
count++;
printNumPattern(num1 - num2, num2);
} else {
x = 1;
if (count >= 0) {
System.out.print(num1 + " ");
count--;
if (count < 0) {
System.exit(0);
}
printNumPattern(num1 + num2, num2);
}
}
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int num1;
int num2;
num1 = scnr.nextInt();
num2 = scnr.nextInt();
printNumPattern(num1, num2);
}
}
See attachment for sample output
