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Misha Larkins [42]
4 years ago
13

An equation is shown below:

Mathematics
1 answer:
Viktor [21]4 years ago
5 0
Distribute the 6 to 2x - 11
12x - 66 + 15 = 21
12x = 72
x = 6
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In ΔRST, the measure of ∠T=90°, RS = 4.9 feet, and ST = 2.7 feet. Find the measure of ∠S to the nearest tenth of a degree.
leva [86]

Step-by-step explanation:

step 1. a diagram is important and can be uploaded. you will get a quicker answer with a diagram

step 2. triangle RST is a right triangle so we can use trigonometry to find <S

step 3. the adjacent side of <S is ST and the hypotenuse is RS so we will use cos

step 4. cosS = adj/hyp = ST/RS = 2.7/4.9

step 5. <S = 56.6° using inverse cos.

6 0
3 years ago
Read 2 more answers
What is the area of the figure in square mm
grandymaker [24]

Answer:

8125 mm

Step-by-step explanation:

Not that sure

5 0
3 years ago
Factor 49x^4 - 4=0 <br><br><br> (Y’all please help this is due in a couple of hours)
Stels [109]

Answer:

49 x^4 - 4 = 0

(7 x^2 - 2) (7 x^2 + 2) = 0    

Only the first term will have real roots

7 x^2 = 2

x = (2 / 7)^1/2 = .535 or -.535

4 0
3 years ago
How do you find the range of a function?
NISA [10]
<span>For more difficult cases, it may be easier to draw the graph first using the domain if possible and then determine the range graphically.See if you can find the inverse function. The domain of a function's inverse function is equal to that function's range.<span>Check to see if the function repeats.</span></span>
8 0
4 years ago
While going to the mountain, John approximated the angle of the elevation to the top of the hill to be 25 degrees. After walking
Allisa [31]
There are several ways of going about this problem, but just know that it all boils down to triangles and the rules/laws of triangles.
So we start by making a large right triangle, because the hill is vertical with the horizontal ground, with 25° as the left angle (where John looks up to top), 90° is the right angle (where ground meets hill base). So we see that the top side of the triangle is the hypotenuse, and equals the line of sight from John to hilltop.
Now we've got additional information that if John walks 350ft towards the hill, his angle of elevation increases by 14. So that = 25+14 = 39. How does that possibly help us?? Well now we can make 2 triangles inside of the one we've already made. So that now we have the triangle base split between the left angle of 25° and where he stopped 350ft to the right of that.
Now the supplement of 39 is 141, and the remaining piece of that too left triangle = 180-25-141 = 14. [See attached drawing].
What does that mean? Well now we have a triangle, where we know all 3 angles and 1 side --> we can find another side by the law of sines:
If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of sines states:
a÷sinA = b÷sinB = c÷sinC
[See attached image]
We really need the hypotenuse to then find our hill height, so we'll make hypotenuse = side b in attached image. That being so, then its opposite angle (B) = 141. And the top right angle (C) = 14 with its opposite side (c) = 350ft.
Now we only need b÷sinB = c÷sinC
So b/sin141 = 350/sin14 --> b = 350sin141/sin14 = 350×.63/
b = 220.3/.24 = 910.47 ft
Now that's our hypotenuse, so using our original large right triangle, we can use right triangular trig. to solve. Let's make the right side, our hill height, equal to x.
Sin ¥ = opp. side / hypotenuse -->
Sin ¥ = x / hypotenuse
Sin25 = x / 910.5
x = 910.5×sin25 = 910.5×.423
x = 384.8 ft

4 0
3 years ago
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