I NEED HELP WITH THIS I DONT GET IT

I need help please and thank you

myrzilka [38]

Answer:

3

Step-by-step explanation:

Slope = y2- y1/ x2- x1

= 4 - (-2) / 3 -1

= 4+2/ 2

=6/2 = 3

4 0

3 years ago

The formula for a trapezoid relates the area A, the two bases, a and b, and the height, h. A=(a+b)/2 h Solve for a.

yKpoI14uk [10]

Answer:

$a=\frac{2A}{h}-b$

Step-by-step explanation:

Hello, I think I can help you with this.

According to the information provided in the problem, the area of a trapezoid is given by

$A=\frac{a+b}{2} *h\\$

Step 1

solve for a, it means isolate a

$A=\frac{a+b}{2} *h\\divide\ both\ sides\ by\ h\\\\\frac{A}{h}= \frac{\frac{a+b}{2} *h}{h} \\\frac{A}{h}=\frac{a+b}{2}\\\\Now, multiply\ both\ sides\ by\ two\\\\ 2*\frac{A}{h}=2*\frac{a+b}{2}\\2*\frac{A}{h}=a+b\\\frac{2A}{h}=a+b\\\\subtract\ b\ for\ both\ sides\\\frac{2A}{h}-b=a+b-b\\a=\frac{2A}{h}-b$

Have a good day.

5 0

3 years ago

A particle moves along the curve below. y = √ 3 + x 3 y=3+x3 As it reaches the point ( 1 , 2 ) (1,2), the y y-coordinate is incr

nydimaria [60]

Answer:

The x-coordinate of the point changing at ¼cm/s

Step-by-step explanation:

Given

y = √(3 + x³)

Point (1,2)

Increment Rate = dy/dt = 3cm/s

To calculate how fast is the x-coordinate of the point changing at that instant?

First, we calculate dy/dx

if y = √(3 + x³)

dy/dx = 3x²/(2√(3 + x³))

At (x,y) = (1,2)

dy/dx = 3(1)²/(2√(3 + 1³))

dy/dx = 3/2√4

dy/dx = 3/(2*2)

dy/dx = ¾

Then we calculate dx/dt

dx/dt = dy/dt ÷ dy/dx

Where dy/dx = ¾ and dy/dt = 3

dx/dt = ¾ ÷ 3

dx/dt = ¾ * ⅓

dx/dt = ¼cm/s

The x-coordinate of the point changing at ¼cm/s

7 0

3 years ago

How do you solve (3x+)(x+3), I dont want the answer, I just want to know how to solve it in complete sentences.

artcher [175]

Answer:

???????????//?///

Step-by-step explanation:

7 0

3 years ago

The function h(x) = x2 + 14x + 41 represents a parabola.

defon

Part A:

$h(x)= x^{2} +14x+41$

The first step of completing the square is writing the expression $x^{2} +14x$ as $(x+7)^{2}$ which expands to $x^{2} +14x+49$ .

We have the first two terms exactly the same with the function we start with: $x^{2}$ and $14x$ but we need to add/subtract from the last term, 49, to obtain 41.

So the second step is to subtract -8 from the expression $x^{2} +14x+49$

The function in completing the square form is
$h(x)= (x+7)^{2}-8$

Part B:

The vertex is obtained by equating the expression in the bracket from part A to zero

$x+7=0$
$x=-7$

It means the curve has a turning point at x = -7

This vertex is a minimum since the function will make a U-shape.
A quadratic function $a x^{2} +bx+c$ can either make U-shape or ∩-shape depends on the value of the constant $a$ that goes with $x^{2}$ . When $a$ is (+), the curve is U-shape. When $a$ (-), the curve is ∩-shape

Part C:

The symmetry line of the curve will pass through the vertex, hence the symmetry line is $x=-7$

This function is shown in the diagram below

3 0

4 years ago

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