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4 years ago

Simplify (xy)^-3/(x^-5y)^3

1 answer:

6 0

$Use:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\a^n:a^m=a^{n-m}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^{-n}=\left(\frac{1}{a}\right)^{n}\\==================================\\\frac{(xy)^{-3}}{(x^{-5}y)^3}=\frac{x^{-3}y^{-3}}{(x^{-5})^3y^3}=\frac{x^{-3}y^{-3}}{x^{-15}y^3}=x^{-3-(-15)}y^{-3-3}=\boxed{x^{12}y^{-6}=\frac{x^{12}}{y^6}}$

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Please help me asap

topjm [15]

To subtract fractions, we need an lcd( lowest common denominator)

8. the lcd is 42 because it’s the smallest number that 6 and 7 are both factors of. the lcd is the bottom of the fraction

to make the denominator of (4/7) 42, we will multiply the top and bottom by 6 and we get (24/42)

to make the denominator of (3/6) 42, we will multiply the top and bottom by 7 and we get (21/42)

these two numbers now have the same denominator so we subtract them

24/42 - 21/42 = 3/42 which simplifies to 1/14

9. since these fractions already have a common denominator, we will make them mixed fractions

-5(2/7) as a mixed fraction. first multiply 5*7 which is 35. now add 2 which is 37. our mixed fraction is -37/7

-1(5/7) as a mixed fraction. multiple 1*7 which is 7. now add 5 which is 12. our mixed fraction is -12/7

now subtract (-37/7) - (12/7) and we get -49/7 which simplifies to -7

3 0

3 years ago

Will has 2 quarters, 6 dimes, some nickels, and 4 pennies. If the ratio of pennies to the total number of coins he has is 1:5, h

Mamont248 [21]

Answer:

8 nickels

Step-by-step explanation:

Let n be the number of nickels.

4: (2+ 6 + 4 + n) = 1:5

4÷(12 + n) = 1÷5

4 x 5 = 1 x (12 + n)

20 = 12 + n

n = 8

4 0

3 years ago

What’s a simple definition of the term Covalent Bond?

weeeeeb [17]

Answer:

A chemical bond that involves the sharing of electron pairs between atoms.

Step-by-step explanation:

7 0

3 years ago

Select the correct answer. What is the completely factored form of this polynomial? 2x5 + 12x3 − 54x A. 2x(x2 + 3)(x + 9)(x − 9)

Valentin [98]

Answer:

Step-by-step explanation:

2x(x^4 + 6x^2 - 27)

x^4 + 6x^2 - 27 = 0

x^2 = y

y^2+ 6y - 27 = 0

(y+9)(y-3) = 0

(x^2+9)(x^2-3) = 0

2x(x^2-3)(x^2+9)

3 0

3 years ago

Read 2 more answers

Find the cosine of angle p

zlopas [31]

Answer: last option

Step-by-step explanation:

You need to remember the identity:

$cos\alpha=\frac{adjacent}{hypotenuse}$

You need to find the cosine of angle P, then, you can identify in the figure that:

$adjacent=PR=21\\hypotenuse=PQ=29\\\alpha=P$

Therefore, the next step is substitute these values into $cos\alpha=\frac{adjacent}{hypotenuse}$ , then you get:

$cos(P)=\frac{21}{29}$

You can observe that this matches with the last option.

6 0

3 years ago