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olga2289 [7]
2 years ago
15

Helpppp PLZZZZZZZZZZZZ and thank you

Mathematics
1 answer:
charle [14.2K]2 years ago
6 0

Answer:

1. a- rate is 3

b. 25 sec

c. 150 meters

d. d= 3/t

2. Roxanna

a. Jose 35

Marie 49

Melanie 63

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Given right triangle MNL what is the value of cos(M)?
FromTheMoon [43]

Step 1

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

ML^{2} =NL^{2} +MN^{2}

Solve for MN

MN^{2}=ML^{2} -NL^{2}

in this problem

ML=25\ units\\ NL=15\ units

Substitute in the formula above

MN^{2}=25^{2} -15^{2}

MN^{2}=400

MN=20\ units

Step 2

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}

adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units

Substitute

cos (M)=\frac{20}{25}

cos (M)=\frac{4}{5}

cos (M)=0.8

therefore

The answer is

The value of cos(M) is equal to 0.8


6 0
3 years ago
To make the expression 4x-2 + (2x + 4) equivalent to 2(6x + 7), what must be the value in the box?
podryga [215]

4x - 2 + (2x + 4) = 2(6x + 7) \\

4x - 2 + 2x + 4 = 12x + 14

Simplification

6x + 2 = 12x + 14

Subtract sides 2

6x + 2 - 2 = 12x + 14 - 2

Simplification

6x = 12x + 12

Subtract sides -12x

6x - 12x = 12x - 12x + 12

Simplification

- 6x = 12

Divided sides by -6

\frac{ - 6}{ - 6}x =  \frac{12}{ - 6} \\

x =  - 2

It is must be in the box buddy.

And we're done...♥️♥️♥️♥️♥️

5 0
3 years ago
-5x^2+17x + -x^2+17 sum
Firdavs [7]

I think -6x^2+17x+17 Hope it helps

4 0
3 years ago
Read 2 more answers
Which type of human body cell would you except to have the most amount of folding in the mitochondria? A. Appendix B. Liver C. H
rosijanka [135]
C. Heart

this is because the heart is more muscle than anything! Muscle cells have loads of mitochondria and the mitochondria themselves are even more efficient than your average mitochondria. 
5 0
3 years ago
How do you do inequalities
sineoko [7]

Answer:

See description below.

Step-by-step explanation:

An inequality is an equation with more than one solution and they use <, >, \leq or \geq. There are a number of ways to work with inequalities.

Solving: To solve inequalities in one variable, treat it just like an equation. Solve using inverse operations. If you divide or multiply by a -1 then be sure to flip the sign. For example, if you have > then it becomes <.

Graphing on a number line: To graph inequalities in one variable, use a number line. Plot a point on the number line with an open circle then an arrow pointing toward the solution set. If you have an equal to, you would shade in the open circle.

Solving: To solve inequalities in two variables, you need a system meaning more than one. You solve it like a system of equations by graphing.

Graphing: To graph inequalities with two variables, graph each in y=mx+b form using the y-intercept and slope. Connect the points with a dashed line unless equal to. Equal to inequalities have a solid line. To show the solution set, shade the side of the inequality which (x,y) points make it true. To find this, test a point by substituting into the inequalities.

5 0
2 years ago
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