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Ivan
3 years ago
13

Please solve! Evaluate the function.

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer:

(h o g)(5) = 20

Step-by-step explanation:

(h o g)(5) = h(g(5)) <em>This is two ways of writing the expression</em>

g(x) = \sqrt{5x}  h(x) = 3x + 5 <em>g(x) and h(x) are your "plug-ins" for the expression</em>

g(5) = \sqrt{5(5)} = \sqrt{25} = 5 <em>This is how you would solve for plugging in 5 to g(x)</em>

<em>Whatever you get for g(5) {the answer to it} is what you will be plugging into h(x); x being equal to g(5).</em>

h(5) = 3(5) + 5 = 15 + 5 = 20  

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2 years ago
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
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