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VladimirAG [237]
3 years ago
13

write and solve an inequality to determine how many hours she must train if she burns an average of 750 calories per hour and ea

ts a total of 8000 calories​
Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

The required inequality: 8000-750h\leq 2000

She must train at least 8 hours.

Step-by-step explanation:

Consider the provided information.

An athlete wants to maintain a net caloric intake of no more than 2,000 calories for the day.

We need to determine how many hours she must train if she burns an average of 750 calories per hour and eats a total of 8000 calories​.

Let the number of hours is h.

She burns an average of 750 calories per hour so for h hours she will burns 750h calories.

She want to maintain no more than 2,000 and she eats a total of 8000 calories​.

Therefore, the required inequality:

8000-750h\leq 2000

Now solve the inequality as:

-750h\leq 2000-8000

-750h\leq -6000

h\geq \frac{-6000}{-750}

h\geq 8

Hence, she must train at least 8 hours.

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Answer:

$3,000

Step-by-step explanation:

There two possible outcomes:

There is a 3/4 chance that the bid is rejected for a value of -$1,400

There is a 1/4 chance that the bid is accepted for a value of $17,600 - $1,400.

The expected value of the situation is:

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3 years ago
Real Answers Only!!!!
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Answer:

The correct answer is C) Reflection across the Y-axis.

Step-by-step explanation:

This is because only the x-coordinates changed. If these coordinates were reflected across both the x and y axis' the sign of both the x and y coordinates would have changed. When  you reflect a point across the x axis, the y-coordinates change their sign. When you <u><em>reflect </em></u><u>a point across the y axis</u>, the <u>x-coordinates change</u> their sign.

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3 years ago
The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge
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Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

5x+4y+5z=-1

x+y+2z=1

2x+y-z=-3

Firs we find determinant of system of equations

Let a matrix A=\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right] and B=\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]

\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}

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Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply R_1\rightarrow R_1-4R_2 and R_3\rightarrow R_3-2R_2

\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]

ApplyR_2\rightarrow R_2-R_1

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Apply R_3\rightarrow R_3+R_2

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]

Apply R_3\rightarrow- \frac{1}{2} and R_2\rightarrow R_2-R_3

\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Apply R_1\rightarrow R_1-R_3

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

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Step-by-step explanation:

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