The GCF of those three monomials is y².
First, we have to find the z scores of $4 and $9.50.
Z₁ = ($4 - $6.50)/$2.25 = -1.11
Z₂ = ($9.50 - $6.50)/$2.25 = 1.33
Then, using a z score table, we find the probability of 1.33 and -1.11, and subtract them to determine the probability in between.
0.9082 - 0.1335 = 0.7747 or 77.47%.
Answer:
30) A) 0 / 15 = 0
31) A) 0/28 = 0
Step-by-step explanation:
30)
0 / 15 = 0
15/0 undefined
15 + 0 = 15
15 - 0 = 15
Answer:
0 / 15 = 0
31) Answer: A) 0/28 = 0
Answer:
47.3 m³
Step-by-step explanation:
The garden shed is made up of a rectangular prism and a pyramid.
<h3><u>Volume of a rectangular prism</u></h3>

<h3><u>Volume of a pyramid</u></h3>
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From inspection of the given diagram, the slant height of the pyramid is 3.5 m.
Calculate the perpendicular height of the pyramid using Pythagoras Theorem:

Therefore:

<h3><u>Volume of the garden shed</u></h3>

Step-by-step explanation:
(i). a+(b+c) = (a+b)+c
-35+(10-5) = (-35+10)+(-5)
-35+5 = -25-5
-30 = -30
(ii). a×(b+c) = a×b + a×c
-35 × [10+(-5)] = -35×10 + -35×-5
-35 × (10-5) = -350 + 175
-35 × 5 = -350 + 175
-175 = -175