12 km<br> 9 km<br> What is the length of the hypotenuse?<br> C =<br> kilometers

Rectangle OPEN has diagonals intersecting at S. If m∠ENP=42 find m∠ EON, m∠ONP, m∠OSP, and m∠PSE

poizon [28]

Answer:

m∠EON = 48°

m∠ONP = 48°

m∠PSE = 90°

4 0

3 years ago

What has the same value as 3/4

ch4aika [34]

The decimal form, which is equivalent to 3/4, is .75

Other fraction forms of 3/4, would be also 6/8, 9/12, 12/16, 15/20, 18/24, 21/28

8 0

3 years ago

Read 2 more answers

Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, âˆ’1), B(4, âˆ’3, 0), C(1

zavuch27 [327]

Answer:

Angle at vertex A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19 x 2√5)= 10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19 x √19)= (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19 x 2√5)= 10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex A : 59.2° B: 61.7° C : 59.1°

7 0

3 years ago

Which graph is the solution to this system y-4x=-1y+x=4

natali 33 [55]

First, let's find the x and y intercepts

In the first equation

y - 4x = -1

Put x =0

y= - 1

(0, -1)

Put y=0 and the n solve for x

0 - 4x = -1

-4x = -1

x=0.25

(0.25 , 0)

The points for the first equation is (0, -1 ) and (0.25, 0)

Next is to find the intercts for the second equation

y + x = 4

put x=0

y = 4

(0, 4)

Put y =0

0 + x = 4

x = 4

( 4, 0)

The points for the second equation are;

(0, 4) and (4, 0)

Below is the graph

4 0

1 year ago

Find y. A. √22 B. 8 C. √42 D. 4

Elina [12.6K]

Answer:

$\Large \boxed{\mathrm{D. \ 4}}$

Step-by-step explanation:

The triangle is a right triangle.

We can use trigonometric functions to solve the problem.

tan θ = opp/adj

tan 30 = y/(4√3)

y = 4√3 tan 30

y = 4

7 0

3 years ago

12 km 9 km What is the length of the hypotenuse? C = kilometers