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3 years ago

12 km 9 km What is the length of the hypotenuse? C = kilometers

Mathematics

1 answer:

siniylev [52]3 years ago

3 0

Answer: 13km

Step-by-step explanation:

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Simplify (x - y + 1) - (x + y - 1)

bulgar [2K]

(x - y + 1) - (x + y - 1)

x - y + 1 - x - y + 1

= (x - x) + (y - y) + (1 + 1)

= -2y + 2

In short, Your Answer would be: -2y + 2

Hope this helps!

3 0

3 years ago

Read 2 more answers

Plz help been stuck on this for awhile

Kazeer [188]

Answer:

d = $\sqrt{74}$ or 8.60

Step-by-step explanation:

(5, 8) (-2, 3)

Let 5 = $x_{1}$

8 = $y_{1}$

-2 = $x_{2}$

3 = $y_{2}$

Plug in the values into the equation to get the distance:

d = $\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }$

d = $\sqrt{(-2-5)^{2} + (3-8)^{2} }$

d = $\sqrt{(-7)^{2} + (5)^{2} }$

d = $\sqrt{49 + 25}$

d =  $\sqrt{74}$ or 8.60

7 0

3 years ago

Ln x + ln (x + 1) = ln 56

Leni [432]

Answer:

x=7

Step-by-step explanation:

ln x +ln(x+1)=ln 56

ln x(x+1)=ln 56

so x(x+1)=56

x^2+x-56=0

(x+8)(x-7)=0

x= -8 or x=7

and lnx,x>0

so x=7

3 0

3 years ago

Could someone help me on question 1 thx

Ghella [55]

The answer is A!!! Hope that helped :)

4 0

2 years ago

Hello can you please help me posted picture of question

jarptica [38.1K]

4x^6+2x^5-2x+8+2x^8+4x+2=
2x^8+4x^6+2x^5+(4-2)x+10=
2x^8+4x^6+2x^5+2x+10

Answer: Option B: 2x^8+4x^6+2x^5+2x+10

7 0

3 years ago