Question

Which function has real zeros at x = −10 and x = −6?

Answer 1

Answer:

Option (a) is correct.

$f(x)=x^2+16x+60$

Step-by-step explanation:

Given :A function has real zeros at x = −10 and x = −6 .

We have to find the function that has real zeros at x = −10 and x = −6.

Consider real zeros at x = −10 and x = −6.

x = - 10 ⇒ x + 10 = 0

x = - 6 ⇒ x + 6 = 0

Multiply both zeroes, we have,

$(x+10)(x+6)$

Apply Distributive rule,

$(a+b)(c+d)=ac+ad+bc+bd$

we have,

$(x+10)(x+6)=x^2+10x+6x+60$

Simplify, we have,

$(x+10)(x+6)=x^2+16x+60$

Thus, $f(x)=x^2+16x+60$

Option (a) is correct.

Answer 2

Answer:

A. on edge.

Step-by-step explanation:

king of brainly (2020)