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castortr0y [4]
3 years ago
7

Find the area of the trapezoid when height = 5in, base1 = 12in, and base2 = 15in.

Mathematics
2 answers:
Ann [662]3 years ago
8 0
Use this formula: 1/2*h(a+b)
myrzilka [38]3 years ago
5 0
A= (a+b)/2*h
A=(12+15)/2*5
A=(27/2)*5
A=13.5*5
A=67.5in
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Answer:

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y intercept (0,-6), x-intercept (-2,0): y = -3x -6

y intercept (0,8), x-intercept (1.6,0): y = -5x + 8

y intercept (0,7), x-intercept (-1.4,0): y = 5x + 7

Step-by-step explanation:

y = mx + b

*note: b is the y intercept

<u>1. y intercept (-6,0), x-intercept (0,-8)</u>

m = \frac{-8 - 0}{0 - (-6)}= \frac{-8}{6}  = \frac{-4}{3}\\y =  \frac{-4}{3}x + b\\y = \frac{-4}{3}x -8

<u>2.y intercept (0,-6), x-intercept (-2,0)</u>

<u />m = \frac{0 - (-6)}{-2 - 0} = \frac{6}{-2}  = -3\\y = -3x + b \\y = -3x -6<u />

<u>3. y intercept (0,8), x-intercept (1.6,0)</u>

<u />m = \frac{0 - 8}{1.6 - 0}= \frac{-8}{1.6} = -5\\y = -5x + b\\y = -5x + 8<u />

<u>4. y intercept (0,7), x-intercept (-1.4,0)</u>

<u />m = \frac{0 - 7}{-1.4 - 0} = \frac{-7}{-1.4}= 5 \\y = 5x + b\\y = 5x + 7<u />

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