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skad [1K]
3 years ago
14

I am an odd number that is less than 10 and is not the number of sides on a triangle. I can be divided by three.What number am I

?
Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0
9 if its odd and 3×3 is 9 so.. thats ur answer
Tju [1.3M]3 years ago
6 0
Six would be the possible solution because if not three and is divided by three and is also less than ten
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Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

\frac{x^a}{x^b}=x^{a-b}

x^0=1

(x^a)(x^b)=x^{a+b}

x^{-a}=\frac{1}{x^a}


\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=

\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=

\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=

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(7^{-5-(-5)})(2^{0-3})=

(7^0)(2^{-3})=

\frac{1}{2^3}=

\frac{1}{8}

7 0
2 years ago
if marcus used to get paid $45 a day and now got a raise to $63 a day what percent increase to his new salary
anygoal [31]
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8 0
2 years ago
What is 6x-3x<br> need help
Andreas93 [3]

Answer:

(6x + (-3)) = 3x


4 0
3 years ago
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Alja [10]
Subtract x
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find  line and shade down , including (0,0)

any point there is a solution
(1,1)
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7 0
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-Dominant- [34]

Answer:

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Step-by-step explanation:

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