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3 years ago

Need help please :)

Mathematics

2 answers:

madam [21]3 years ago

8 0

Acute. this triangle is acute because a right triangle would have a 90 not a 60.

swat323 years ago

4 0

Answer:

acute

Step-by-step explanation:

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I need help with this plz

Alisiya [41]

Answer:Mmm

Step-by-step explanation:

I am doing the work I will thell you the answer

5 0

2 years ago

5/7 divided by 20/5 <br> then simply it completely

Pavlova-9 [17]

Answer:

5 / 28

Step-by-step explanation:

5/7 ÷ 20/5

= 5/7 x 5/20

= (5 x 5) / (7 x 20)

= 25 / 140 (divide numerator and denominator by 5)

= 5 / 28

5 0

3 years ago

9x = 3x - 36 solve please

tatyana61 [14]

Answer:

x=-6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

3 years ago

Tom ate 1/2 of the leftovers. How much pie in all did he eat

melisa1 [442]

1/2+1/2=2/2=1 so 1/2 was eaten and the other half was leftovers.

8 0

3 years ago

Read 2 more answers