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Butoxors [25]
3 years ago
5

one week a student exercised 2 hours at school and another 2/3 of an hour at home. if 1/6 of the students total exercise came fr

om playing basketball, how much time did the student spend playing basketball that week?
Mathematics
2 answers:
Marianna [84]3 years ago
8 0
2 hours + 40 min = 160 min
160 min / 6 = 26.6666667
Answer: Approx. 27 minutes
seropon [69]3 years ago
4 0

Answer:

(roughly) 27

Step-by-step explanation:

The student spent 2 2/3 hours exercising this week, which also transfers to 160 minutes. Divide this by 6 to find 1/6 of his/her time. The result is 26.67 (rounded), so roughly 27 minutes were spent on basketball. to check, you can multiply 26.67 by 6 to get 160.02, which rounds back to 160 minutes.

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Pls help.question attached.
Svet_ta [14]

Answer:

-1. is -3/7

Step-by-step explanation:

6×-4/11*7 ÷ (4/3×6/11)

-24/11×7 ÷ (4/3×6/11)

-24/77 ÷ (4/3×6/11)

-24/77 ÷ (24/3×11)

-24/77 ÷ 24/33

-24/77 × 33/24

-1/77 × 33

-33/77

-3/7

8 0
3 years ago
James was trying to sleep one night but there was too much noise around him. His clock ticked every
g100num [7]

Answer:

<em>It will occur zero times between midnight and one o'clock.</em>

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

Three events keep James from sleeping: his clock ticking every 20 seconds, a tap dripping every 15 seconds, and his dog snoring every 27 seconds.

All three events happened together at midnight. They will happen together again the first time the numbers 20, 15, and 27 have a common multiple. This is the LCM.

List the prime factors of each number:

20: 2,2,5

15: 3,5

27: 3,3,3

Now multiply all the factors the maximum number of times they appear:

LCM=2*2*3*3*3*5=540

(a) All the events will happen together again after 540 minutes.

(b) Since 540 minutes = 9 hours, this event won't happen again until 9 am. Thus, it will occur zero times between midnight and one o'clock.

4 0
3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
Circle U is shown. Chords R T and Q S intersect at a point forming 4 angles. The top left angle is angle 1, and the top right an
Dima020 [189]

Based on the calculations, the measures of angles 1 and 2 are 50° and 135° respectively.

<h3>What is the theorem of intersecting chord?</h3>

The theorem of intersecting chord states that when two (2) chords intersect inside a circle, the measure of the angle formed by these chords is equal to one-half (½) of the sum of the two (2) arcs it intercepts.

By applying the theorem of intersecting chord to circle U shown in the image attached below, we can infer and logically deduce that angle 1 will be given by this formula:

m∠1 = ½(53 + 47)

m∠1 = ½(100)

m∠1 = 50°.

Since angles 1 and 2 are linear pair, they are supplementary angles. Thus, we have:

m∠1 + m∠2 = 180°

m∠2 = 180 - m∠1

m∠2 = 180 - 50

m∠2 = 130°.

Read more on intersecting chords here: brainly.com/question/27251228

#SPJ1

6 0
2 years ago
Read 2 more answers
Mark has been watching 16 movies for the past x months. Max has been trying to keep up with his pace but has only been able to w
egoroff_w [7]

Mark = 16

Max = 8

16 + 8 = 24

144/24 = 6

Option D. 6 months

4 0
3 years ago
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