Find the distance between the two points (-2,5) (4,-2)

qwelly [4]

First you would have to multiply 12 times 5 (60) then multiply 7 times 18 (126) you subtract both [ 126 - 60] = (66) that would be your final answer. They both need to have worked 66 minutes to have the same number of boxes.

4 0

3 years ago

HELP !! Calculate the cost of manufacturing a standard cereal box if cardboard costs $0.05 per square inch.

Xelga [282]

You are right, with the total surface. next thing u want to do is multiply 290 and 0.05 and you should get your answer

8 0

3 years ago

Read 2 more answers

Can someone help me solve this problem 1.8 divided by 12

EleoNora [17]

Answer:

0.15 I believe

Step-by-step explanation:

you just divide

4 0

3 years ago

The US Department of Energy reported that 49% of homes were heated by natural gas. A random sample of 338 homes in Oregon found

Furkat [3]

Answer:

$z=\frac{0.438 -0.49}{\sqrt{\frac{0.49(1-0.49)}{338}}}=-1.912$

The p value for this case would be given by:

$p_v =2*P(z$

For this case the p value is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.49 or 49%

Step-by-step explanation:

Information given

n=338 represent the random sample taken

X=148 represent the homes in Oregon were heated by natural gas

$\hat p=\frac{148}{338}=0.438$ estimated proportion of homes in Oregon were heated by natural gas

$p_o=0.49$ is the value that we want to test

represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to check if the true proportion of interest is 0.49, then the system of hypothesis are.:

Null hypothesis: $p=0.49$

Alternative hypothesis: $p \neq 0.49$

The statitic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.438 -0.49}{\sqrt{\frac{0.49(1-0.49)}{338}}}=-1.912$

The p value for this case would be given by:

$p_v =2*P(z$

For this case the p value is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.49 or 49%

8 0

4 years ago

Please just (c)fog-¹

omeli [17]

f(x) = 1/(1 - x)

g(x) = (x - 1)/x

The inverse functions f ⁻¹(x) and g ⁻¹(x), if they exist, are such that

f( f ⁻¹(x) ) = x

g( g ⁻¹(x) ) = x

So we have

f( f ⁻¹(x) ) = 1/(1 - f ⁻¹(x) ) = x

Solve for f ⁻¹(x) :

1 = (1 - f ⁻¹(x) ) x

1 - f ⁻¹(x) = 1/x

f ⁻¹(x) = 1 - 1/x

f ⁻¹(x) = (x - 1)/x

and so f ⁻¹(x) = g(x).

Similarly, you can solve for g ⁻¹(x) :

g( g ⁻¹(x) ) = (g ⁻¹(x) - 1) / g ⁻¹(x) = x

1 - 1/g ⁻¹(x) = x

1/g ⁻¹(x) = 1 - x

g ⁻¹(x) = 1/(1 - x)

So we know f(x) and g(x) are inverses of one another,

f ⁻¹(x) = g(x)

g ⁻¹(x) = f(x)

Then

(a) (f o g)(x) = x

(b) (g o f ⁻¹)(x) = g(g(x)) = (g(x) - 1)/g(x) = 1 - 1/g(x) = 1 - x/(x - 1) = 1/(1 - x)

(c) (f o g ⁻¹)(x) = f(f(x)) = 1/(1 - f(x) ) = 1/(1 - 1/(1 - x)) = 1/(x/(x - 1)) = (x - 1)/x

8 0

3 years ago